(3)4x+1=(1/9)^x+1

Solution for (3)4x+1=(1/9)^x+1 equation:

(3)4x+1=(1/9)^x+1

We move all terms to the left:

(3)4x+1-((1/9)^x+1)=0


Domain of the equation: 9)^x+1)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

34x-((+1/9)^x+1)+1=0

We multiply all the terms by the denominator


34x*9)^x+1)-((+1*9)^x+1)+1=0

We add all the numbers together, and all the variables

34x*9)^x+1)-(9^x+1)+1=0

Wy multiply elements

306x^2=0

a = 306; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·306·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{612}=0$